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Spiral Matrix

LeetCode

01 · Question

Given an m x n matrix, return all elements of the matrix in spiral order.

Example 1:

  • Input: matrix = [[1,2,3],[4,5,6],[7,8,9]]
  • Output: [1,2,3,6,9,8,7,4,5]

Example 2:

  • Input: matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]]
  • Output: [1,2,3,4,8,12,11,10,9,5,6,7]

02 · Solution

Reference solution

1def spiralOrder(matrix: List[List[int]]) -> List[int]:
2 if not matrix: return []
3 res = []
4 top, bottom = 0, len(matrix) - 1
5 left, right = 0, len(matrix[0]) - 1
6
7 while top <= bottom and left <= right:
8 # Traverse Right
9 for i in range(left, right + 1):
10 res.append(matrix[top][i])
11 top += 1
12
13 # Traverse Down
14 for i in range(top, bottom + 1):
15 res.append(matrix[i][right])
16 right -= 1
17
18 if top <= bottom:
19 # Traverse Left
20 for i in range(right, left - 1, -1):
21 res.append(matrix[bottom][i])
22 bottom -= 1
23
24 if left <= right:
25 # Traverse Up
26 for i in range(bottom, top - 1, -1):
27 res.append(matrix[i][left])
28 left += 1
29
30 return res